27-0.02v^2=0

Solution for 27-0.02v^2=0 equation:

27-0.02v^2=0

a = -0.02; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-0.02)·27
Δ = 2.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.16}}{2*-0.02}=\frac{0-\sqrt{2.16}}{-0.04}
=-\frac{\sqrt{}}{-0.04}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.16}}{2*-0.02}=\frac{0+\sqrt{2.16}}{-0.04}
=\frac{\sqrt{}}{-0.04}
$